作者 主题: 橡辊术的伤害到底是怎样计算的?  (阅读 1820 次)

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离线 Stuart

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橡辊术的伤害到底是怎样计算的?
« 于: 2005-08-22, 周一 12:23:21 »
Shillelagh
Transmutation
Level: Drd 1
Components: V, S, DF
Casting Time: 1 standard action
Range: Touch
Target: One touched nonmagical oak club or quarterstaff
Duration: 1 min./level
Saving Throw: Will negates (object)
Spell Resistance: Yes (object)
Your own nonmagical club or quarterstaff becomes a weapon with a +1 enhancement bonus on attack and damage rolls. (A quarterstaff gains this enhancement for both ends of the weapon.) It deals damage as if it were two size categories larger (a Small club or quarterstaff so transmuted deals 1d8 points of damage, a Medium 2d6, and a Large 3d6), +1 for its enhancement bonus. These effects only occur when the weapon is wielded by you. If you do not wield it, the weapon behaves as if unaffected by this spell.

前面的简述里提到,伤害会变成1d10.看来应该是指中型武器的伤害的增进.
但在内容中却说小型武器增进为d8,中型增进为2d6,大型增进为3d6.
如果一个中体型督依德手持木棒,在该法术的影响下,他木棒的伤害是1d10还是2d6?
如果他是小体型的呢?是不是d8的伤害?
如果他是大体型的,是3d6,还是2d8?
 
人不是什么时候都能活得光明正大,本想抬头挺胸前进,却不知何时就会沾一身泥巴。

离线 aland

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橡辊术的伤害到底是怎样计算的?
« 回帖 #1 于: 2005-08-22, 周一 12:56:36 »
1d6的大一号是1D8,1D8再大一号是2D6.

对中型就是这样.
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离线 Area-88

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橡辊术的伤害到底是怎样计算的?
« 回帖 #2 于: 2005-08-22, 周一 17:08:20 »
前面的简述是一个错误,因为3E的Shillelagh就是固定变成1D10伤害,3R的简述照抄3E后却没有按新版本的效果改过来。

 
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